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+# ###
+# Consecutive prime sum
+# Problem 50
+# 
+# The prime 41, can be written as the sum of six consecutive primes:
+# 41 = 2 + 3 + 5 + 7 + 11 + 13
+# This is the longest sum of consecutive primes that adds to a prime below one-hundred.
+# The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.
+# Which prime, below one-million, can be written as the sum of the most consecutive primes?
+# ###
+
+
+from helper.prime import primes_loop, is_prime
+
+
+sumed = []
+ps = []
+max_len = 0
+for p in primes_loop():
+    if p > 20000:
+        break
+    ps.append(p)
+    for i in range(len(ps)):
+        s = sum(ps[i:])
+        if s > 1000000:
+            break
+        if is_prime(s) and len(ps) > max_len:
+            sumed.append(s)
+            max_len = len(ps)
+
+print(sumed[-1])