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-rw-r--r--python/031-coin_sums.py28
1 files changed, 15 insertions, 13 deletions
diff --git a/python/031-coin_sums.py b/python/031-coin_sums.py
index 46c371b..d10b333 100644
--- a/python/031-coin_sums.py
+++ b/python/031-coin_sums.py
@@ -1,7 +1,7 @@
# ###
# Coin sums
# Problem 31
-#
+#
# In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:
# 1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).
# It is possible to make £2 in the following way:
@@ -10,19 +10,21 @@
# ###
-coins = [200, 100, 50, 20, 10, 5, 2, 1]
-solutions = []
+count = 0
-def backtrack(n, sol):
- if sum(sol) > n:
+def solve(coins):
+ s = sum(coins)
+ if s == 200:
+ global count
+ print(count, coins)
+ count += 1
return
- if n == 0:
- solutions.append(sol)
+ if s > 200:
return
- while next_sol(n, sol):
- backtrack(n, sol)
+ for coin in [200, 100, 50, 20, 10, 5, 2, 1]:
+ if len(coins) != 0 and coins[-1] < coin:
+ continue
+ solve(coins + [coin])
-def next_(n, sol):
-
-
-backtrack(10, [])
+solve([])
+print(count)