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# ###
# Coin sums
# Problem 31
#
# In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:
# 1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).
# It is possible to make £2 in the following way:
# 1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
# How many different ways can £2 be made using any number of coins?
# ###
count = 0
def solve(coins):
s = sum(coins)
if s == 200:
global count
print(count, coins)
count += 1
return
if s > 200:
return
for coin in [200, 100, 50, 20, 10, 5, 2, 1]:
if len(coins) != 0 and coins[-1] < coin:
continue
solve(coins + [coin])
solve([])
print(count)
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